BlackMagic

Hey, I did a project that needed this a couple of years ago. I simply took the postcodes and with the help of google maps converted them to a Lat and Long. I then simply found the distance between these two points. This may help: http://www.zipcodeworld.com/samples/distance.php.html

Hi Guys, Im currently working on a project where I need to generate Barcodes for each product in a catalogue. I have done this without any problems. The idea is that these unique barcodes to be printed off, placed on the products and then shipped to the warehouse. I know that a barcode is simply a unqiue string. Therefor.... My Client has asked if, with the help of a Barcode Reader, the stock count in the databasse of each product could be deducted if the item is scanned. Is this possible? The simplest way is to call a webpage and simply deduct the given code by 1, however I dont know if this possible. Am I approaching this the right way? Can someone with any experience in this field please point me in the right direction. It would help an awful lot. Thanks in Advance, BlackMagic

Hi Richard, The problem is that I want my functions to be ableto access the file whilst I dont want users being able to access the file via a URL.

Brill. Lots of food for thought! Thanks!

Thanks Snider DK, But how would I go about this? Basically i want to be able to read the file but not the public. I've had an idea that via ht.access I could please a secret key on the text file i.e 1234. So if you visit settings.txt you get redirect as you will need to go to seetings.txt?secret=1234 in order to access. What do you think?

Hi Guys, I have built an ecommerce solution however I have a text file that contains "senstivie" informaiton. I need to access the text file in order to read its ocntents, however i dont want people to be bale to just access the file via a URL such as /incs/settings.txt in a web browser. Whats the best way to do this? I know I could do this with htacess by redirecting the url away from the file however, this will then not allow me to read it? Any help would be appreciated.. Thanks In Advance

Guys, Sorry. I know how to comment. What I need to do is comment correctly for a software application. i need to know what the correct Style for PHP comments are i.e in Java you have @package, @author etc.

Hi Guys, I need to comment my methods in my classes but am finding it dificult to find a correct style to follow. If i was writing the application in Java or C# I would know what I was doing. Could anyone put me in the right direction? Thanks in advance

To add a row number create a ID in your database table, Make it primary so it is unqiue and then allow it to auto increment so it will always be unique. To count the the total number of rows, mysql has a built in function called mysql_num_rows. Below is an example: <?php $link = mysql_connect("localhost", "mysql_user", "mysql_password"); mysql_select_db("database", $link); $result = mysql_query("SELECT * FROM table1", $link); $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; ?> A full link can be seen here: http://php.net/manual/en/function.mysql-num-rows.php Hope this helps!

Please ignore

Hi Guys, I have a problme with my code and i dont know where. There are no errors being returned for the file im uploading and the directory is 777. Below is the code. Please have a look and put me out of my misery! $allowedExtensions = array("image/gif", "image/jpg", "image/jpeg", "image/png"); if(in_array($_FILES["myImage"]["type"],$allowedExtensions)){ //print_r($_FILES['myImage']); if($_FILES["myImage"]["error"] != 0){ echo "<p class='error'>Error while uploading Image. Please check the file is not corrupt or open.</p>"; }else{ $target_path = "uploads/"; $target_path = $target_path.time()."_". basename( $_FILES['myImage']['name']); if(move_uploaded_file($_FILES['myImage']['tmp_name'], $target_path)) { echo "<p class='success'>Image Uploaded Successfully</p>"; } else { echo "<p class='error'>File was not uploaded.</p>"; } } } else { echo "<p class='error'>The File you have tried to upload is an incorrect file extension. The only files able to be uploaded are gif, jpeg, jpg and png.</p>"; } Thanks In Advance

Thanks Guys. Do you suggest I use an existing MVC such as CakePHP Code Ingniter etc or build my own? Regards

http://www.ajaxdaddy.com/demo-ajax-chat.html Have a look at this. Its very simple and writes the chat window to a text file on your server. You could obviously use a database instead and then password protect the page trying to be accesed.

Hi Guys, I am creating a Ecommerce solution from scratch as a personal project as I am tired of using existing solutions due to fact of not be able to add simple methods and functions with out having to go round the houses. I have also documented this from scratch and feel that the best way to build a robust low cohesive solution is to uase a tried and tested design pattern. This is when I came across model-view-controller. i like the idea but I have never coded one before. Is this a good idea? Is there a better design pattern to be using for an ecommerce solution? Any help would be greatly appreciated. Thanks in advance.

ajaxdaddy.com have a great simple Ajax chatroom - writes to a text file and is really useful.

Hey, Have a look on google for SWFObject to implement your flash into the webpage - this should fix the compatability issues. Thanks Ciaran

How much knowledge do you have of PHP and how big are thwe images going to be? You could store the images in binary form and then write them - this means you would have uniquer images amd they would not be on the server. You could also just store the images for each user and place a unique ID and a time stamp to make sure there unique.

It seems that the overflow:hidden; is the cause of the problem, have you set a height anywhere? I suggest you remove the overflow aspect and check for a set height in your clases.

I suggest that you google PHP sessions. You need to understand how Sessions work and how calling to a database work before you can build something like this on your own. Learn to walk before you learn to run

Yup its easy. Simply set in the css of the text your calling visibility: hidden; Problem solved!

Hey Ash, Have you ever heard of swf object? Its a simple javascript code that is much morte reliable than standard flash injection! See the link below: blog.deconcept.com/swfobject/

Have a look on google for changing images in a database in binary form - that way you could join images up.

So you want to store what you have entered but without a database. You could use text files as A temp database I supose. Quick and easy.

The geniuses of this great forum- someone must know!

Try this. <?php if ($row_pupdata['photothumb1'] == "") { echo "<img src='/NOPHOTO.jpg' width='80' height='80' />"; } else { echo "<img src=".$row_pupdata['photothumb1']." alt='' border='2' align='top' />"; } ?>