ThomasHardy

Hey everyone its a been a while since I was on these forums but I have a new site I would love to hear your views on, the site is Design-Heaven it is a website I launched yesterday that will be publishing articles every Monday, Wednesday and Friday showcasing the best in design from all over the Internet. All views are appreciated and any suggestions for improvement would be fantastic!

I was getting a bit annoyed with checking my RSS feed and my twitter was getting a bit clogged, so i have decided to make myself a twitter which tweets all the stuff from the best web design/design based blogs around the web. Here it is @webdesign_feeds If you know of any blogs which should be included i would love to hear so just drop a comment here and I will take a look at adding it.

Over at one of my sites we are running this giveaway - We are glad to announce that we have teamed up with Crazy Dog T-Shirts who are kindly suppling us with 5 t-shirts which are going to be giving 5 different lucky readers via a simple to enter competition. All you have to do to enter the competition is comment on this post saying anything you like (preferably how great we/crazy dog t-shirts are for running this giveaway!) The winners will be randomly selected and announced at 10PM (GMT) on Sunday 11th April

Thanks a lot ElanMan. That works fine, just out of interest was it possible to do it the way i was trying to with the onclick or onchange?

Hi, I am having a little problem with a form i am trying to create. What i need it to do is when Company is selected it hides the freelance div and shows the company div and vice versa. Here is what i have so far. Javascript function displayElements(number) { switch(number) { case 1: document.getElementById("company").setAttribute("style", "visibility:visible"); break; case 2: document.getElementById("freelance").setAttribute("style", "visibility:hidden"); break; } } HTML <select name="customerType" onclick="displayElements(this.value);"> <option value="0">Type?</option> <option value="1">Freelancer</option> <option value="2" >Company</option> </select> <div id="freelance" style="visibility:visible"> Forename <input type="text" name="forename" id="forename" /> Surname <input type="text" name="surname" id="surname" /> </div> <div id="company" style="visibility:hidden"> Company Name <input type="text" name="companyName" id="companyName" /> </div>

I am having a huge headache with one of my RSS feeds, some how it has managed to generate an error and I can't see where or how to fix it! I am using a wordpress blog and then have burnt the feed over to feedburner, the feed is here - http://feeds.feedburner.com/webdesignerhelp. If anyone can help that would be great, if you need to get access to any more info PM me with an MSN or AIM or gChat and I will chat on there. Thanks, Thomas Hardy

I have 3 twitter accounts (Yes I am greedy!) Personal - @ThomasJHardy Web Designer Help - @WebDesignerHelp Work-Killer - @WorkKiller

Ok I added in what you said above and when I did I got the error when fields weren't filled in but I also get errors when they are!

Thanks that worked perfect, I knew it would be really simple. Right now another bit is a simple way to add a check that age is numerical after it checks everything is filled in?

No they are separate files, is there any easy to make what you just made work from a separate file?.

Argh my mind has gone blank I am stuck on the simpliest of php validation. I have a form where I need to check the user fills in all the boxes but I can't use javascript and can only use PHP, I know its really simple but I cant get it to work! Here is my form that I want the textboxs to be checked on. <form id = "addperson" method = "post" action = "addhome.php"> <p>Namer</p> <input type = "text" name = "name" id = "name" /> <p>Gender</p> <input type = "text" name = "gender" id = "gender" /> <p>Age</p> <input type = "text" name = "age" id = "age" /> <p><input type = "submit" value = "Add" /></p> </form> Here is the php script. <?php include 'database_conn.php'; $name = $_POST['name']; $gender = $_POST['gender']; $age = $_POST['age]; $sql = "INSERT INTO people (name, gender, age) values ('$name', '$gender', '$age')"; header ("Location: admin.php"); mysql_query($sql) or die (mysql_error()); mysql_close($conn); ?> I dont want to use any javascript I just want a simple server validation that if one isn't filled in it will go back to the original form with a error message informing the user to fill all the fields in.

I did try having a bit more jazzy but I wasn't a big fan so I want with plain and simple with a nice sort of background (I knew it wouldn't suit everyones tastes but what can you do). I think I will implement a couple of 'skins' and have it change style everyday so it looks fresher. As said above I did have a bit more vibrant background on while developing it but deciding against, I will probably put a few skins in with a few more colours on. Thanks I do like the hover effects plain and simple is what I was going for But you can see the navigation so atleast you can still browse the site

Hi, I am nearing the completion of my new portfolio and would really love some to hear what you think of it. Link

I have had a very quick play around with the fonts/headings what does everyone think?

Thanks, I will defiently try helvetica neue. Thanks