July 13, 201115 yr Is it possible to pass an argument to a PHP script using include? <html> <body> <?php include 'script.php' ?> </body> </html> Let's say that script.php looks like this: <?php echo 'Hello world!' ?> This will result with "Hello world!" being shown on the screen, but is it possible to decide from outside of the script what it should show? <html> <body> <?php include 'script.php' 'Hello world!' ?> <?php include 'script.php' 'LOL!' ?> <?php include 'script.php' 'Bye' ?> </body </html> And in script.php: <?php echo (argument here) ?> This is of course a very simple example, but imagine if the script.php is extremely big and it has to act slightly different for every page, then this would be very useful. Is it even possible? And yes, I'm a noob at PHP. Edited July 13, 201115 yr by Davve
July 13, 201115 yr uhm, its possible this way: $var = 'ass'; include 'xxx.php'; and in xxx.php: echo $ass; in php the included script is the same scope as the invoker scritp it means that all variables from the current scope are visible.
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