I fudged this script together to check a websites body content and generate a message whether a keyword is present more than twice. only it breaks and doesn't work if the "keyword" is more than one word.

 

How to I make it work so it can cater for multiple words within the "keyword"

 

<?php
$keyword = ($_POST['keyword']); // defined by form
$domainname = ($_POST['url']); // defined by form

$file = file_get_contents($domainname);
$body = preg_replace("/.*<body[^>]*>|<\/body>.*/si", "", $file);{
$bodyp = strip_tags($file);
if (substr_count(strtolower($bodyp), strtolower($keyword)) > 2 ){
       echo "<span class='good'>Yes. </span>Awesome, your keyword is present in the body of your content.";
       }
else {
              echo "<span class='bad'>No. </span>You should really have the keyword your looking for in content of your website.";
       }
      }
?>

 

Cheers people ()

Personally I'd strip all HTML tags using strip_tags() then compare that string using strpos()

Personally I'd strip all HTML tags using strip_tags() then compare that string using strpos()

 

I have striped all html tags...

 

$bodyp = strip_tags($file);

 

When I echo out the result ($bodyp) I get text..which has the two word keyword in, but it tell me that its not there.

I dont know much about substr_count but I suggested using strpos as an alternative, for example...

 

<?php

$keyword = ($_POST['keyword']); // defined by form
$domainname = ($_POST['url']); // defined by form

//tests
$domainname = 'http://news.bbc.co.uk/sport1/hi/football/scot_prem/9028899.stm'; 
$keyword = "kenny miller";

function keyWordCount($keyword, $body) {

   $found = $offset = 0;

   while(!(strpos($body, $keyword, $offset) === false)) {
       $found++;
       $offset = strpos($body, $keyword, $offset)+1;
   }

   return $found;

} 

$file = file_get_contents($domainname);
$body = preg_replace("/.*<body[^>]*>|<\/body>.*/si", "", $file); //this is EXTREMELY CPU intensive!
$bodyp = strip_tags($body);

if (keyWordCount(strtolower($keyword), strtolower($bodyp)) > 2 ) {
   echo "<span class='good'>Yes. </span>Awesome, your keyword is present in the body of your content.";
} else {
   echo "<span class='bad'>No. </span>You should really have the keyword your looking for in content of your website.";
}
?>