I'm cutting out loads of the code here but this should give you a good enough idea..

 

<?php
while($row = mysql_fetch_array($result))

{
//Example URL//  $url = "http://youtube.com/watch?v=abc123";
parse_str($url["query"]);
// ^ Generates $v variable//


$shuffle = array();//Set Shuffle Array//
array_push($shuffle,$v);  //Add Video ID to Shuffle Array//

}

$rand = array_rand($shuffle, 1);

echo "Random Video ID = " . $shuffle[$rand];    ?>

 

Basically what I want to do is get every $v variable and add it to the $shuffle array so I can pick out random values, but when I try this it only seems to add the last $v that was set

 

Thanks @jamesrwhite

A quick glance would make me believe you don't want to re-assign the $shuffle array each time inside the loop. This is basically clearing out the array on each iteration before adding that iteration's $v to the (new) array. Hence by the time the loop finishes, only the last $v has been added (to the new and empty array that was created in that iteration). If you see what I mean?!

 

Anyway, to fix it, delete the line:

 

$shuffle = array();

and place it instead before and outside the loop, like this:

 

$shuffle = array();
while($row = mysql_fetch_array($result))

 

Does that solve (and importantly explain) it for you?

Ahh yh It seems so obvious now..

 

Thanks

array_push isn't really intended for single items to be added to an array

you'd be better off using

$shuffle[] = $v; //Add Video ID to Shuffle Array//